WebSpecific enthalpy (kJ/kg) Specific entropy (kJ/kg-K) Temp. T (°C) Pressure P (kPa) 103 v f vg uf ug hf hg sf sg T ... 4 0.8135 1.0001 157.14 16.812 2380.4 16.813 2508.2 0.06110 9.0506 4 6 0.9353 1.0001 137.65 25.224 2383.2 25.225 2511.9 0.09134 8.9994 6 ... T (°C) Pressure P (kPa) 103 v f vg uf ug hf hg sf sg T Web1. A convergent divergent adiabatic steam nozzle is supplied with steam at 10 bar and 250°c.the discharge pressure is 1.2 bar.assuming that the nozzle efficiency is 100% and initial velocity of steam is 50 m/s. find the discharge velocity. Given Data:- Initial pressure(p 1)=10bar Initial . Temperature(T 1)=250°c . Exit pressure(p 2)=1.2 bar
Solved Problems: Steam Nozzles and Turbines - BrainKart
WebFeb 12, 2024 · In thermodynamics, the change in Gibbs free energy, ΔG, is defined as: (6.2.3.3.1) Δ G = Δ H − T Δ S. where. ΔG = change in Gibbs free energy of the reaction. ΔH = change in enthalpy. ΔS = change in entropy. Δ G o is the change in Gibbs energy when the reaction happens at Standard State (1 atm, 298 K, pH 7). WebLESSON - 23 NUMERICAL PROBLEMS ON HEATING AND EXPANSION OF VAPOUR IN NON-FLOW PROCESSES - I. Problem 23.1: A quantity of steam at 10 bar and 0.85 dryness occupies 0.15 m3. Determine the heat supplied to raise the temperature of the steam to 300°C at constant pressure and percentage of this heat which appears as … checks unlimited out of stock
5.7: Enthalpy Calculations - Chemistry LibreTexts
Web14 At 7 bar, h g = 2762 kJ/kg and since the actual specific enthalpy is given as 2600 kJ/kg, ... 17 From Table 12, u at p = 100 bar and T = 350 o C = 2702 kJ/kg Or by calculation using equation (1.9). From tables of superheated steam (Table 9) at p = 100 bar and T = 350 o C, the enthalpy, h is 2926 kJ/ kg. Using equation (1.9) ... WebQuestion 1 a) Determine the specific enthalpy of steam at 15 bar and 275°C . b) Determine the degree of superheat and entropy of steam at 10 bar and 380 °C. c) A superheated steam at 12.5 MN/m2 is at 650°C .Determine its specific volume. Question 2 WebDec 6, 2024 · How to Solve. You can solve this problem using either joules or calories for heat. Part I: Use the formula q = m·ΔH v in which q = heat energy, m = mass, and ΔH v = heat of vaporization. q = (25 g)x (2257 J/g) q = 56425 … checks unlimited promo code november 2017